Giải thích các bước giải:
Câu 1:
1)
\({H_3}P{O_4}\): Axit photphoric
\({P_2}{O_5}\): Photpho pentaoxit
\(Mg{(OH)_2}\): Magie hidroxit
\(NaN{O_3}\): Natri nitrat
2)
- Bazo: \(Mg{(OH)_2}\)
- Axit: \({H_3}P{O_4}\)
- Oxit: \({P_2}{O_5}\)
- Muối: \(NaN{O_3}\)
Câu 3:
\(\begin{array}{l}
1.\\
F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
FeC{l_2} + 2NaOH \to Fe{(OH)_2} + 2NaCl\\
Fe{(OH)_2} + {H_2}S{O_4} \to FeS{O_4} + 2{H_2}O\\
2.\\
a)2Al + 3C{l_2} \to 2AlC{l_3}\\
b)2Al + 3C{\rm{uS}}{O_4} \to A{l_2}{(S{O_4})_3} + 3Cu
\end{array}\)
Câu 5:
\(\begin{array}{l}
1)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
ZnO + 2HCl \to ZnC{l_2} + {H_2}O\\
2)\\
{n_{{H_2}}} = 0,1mol\\
\to {n_{Zn}} = {n_{{H_2}}} = 0,1mol\\
\to {m_{Zn}} = 6,5g\\
\to {m_{ZnO}} = 14,6 - 6,5 = 8,1g\\
\to {n_{ZnO}} = 0,1mol\\
3)\\
{n_{HCl}} = 2{n_{Zn}} + 2{n_{ZnO}} = 0,4mol\\
\to {m_{HCl}} = 14,6g\\
\to {m_{{\rm{dd}}HCl}} = \dfrac{{14,6}}{{7,3\% }} \times 100\% = 200g
\end{array}\)
