Đáp án:
$C_M(CH_3COONa)=0,75\ M$
Giải thích các bước giải:
$n_{CH_3COOH}=0,1.1,5=0,15\ (mol)$
PTHH:
$CH_3COOH+NaOH→CH_3COONa+H_2O\\ \hspace{0,4cm}0,15 \to \hspace{4,3cm} 0,15\hspace{2,4cm}(mol)$
Ta có: $V_{\text{dd sau pư}}=100+100=200\ (ml)=0,2\ l$
Theo PT: $n_{CH_3COONa}=n_{CH_3COOH}=0,15\ (mol)$
$⇒C_M(CH_3COONa)=\dfrac{0,15}{0,2}=0,75\ M$