`|5/2x-7/2|-|5/8x+3/5|=0`
`⇒|5/2x-7/2|=|5/8x+3/5|`
$⇒\left[ \begin{array}{l}\frac{5}{2}x-\frac{7}{2}=\frac{5}{8}x+\frac{3}{5}\\\frac{5}{2}x-\frac{7}{2}=-\frac{5}{8}x-\frac{3}{5}\end{array} \right.$
$⇒\left[ \begin{array}{l}x=\frac{164}{75}\\x=\frac{116}{125}\end{array} \right.$
Vậy `x=(164)/(75),x=(116)/(125)`.