Từ $A$ kẻ $Ax//m$
Ta có:
$Ax//,$
$⇒\widehat{ADm}=\widehat{DAx}=36^o$ (2 góc so le trong)
Ta có: $Ax//m;m//n$
$⇒Ax//n$
$⇒\widehat{xAC}+\widehat{ACn}=180^o$ (2 góc trong cùng phía)
$⇒\widehat{xAC}+139^o=180^o$
$⇒\widehat{xAC}=41^o$
Nên ta có: $\widehat{DAC}=\widehat{DAx}+\widehat{xAC}=36^o+41^o=77^o$