`|x| + x = 1/3`
`|x| = 1/3 - x`
`⇒` \(\left[ \begin{array}{l}x=\dfrac{1}{3} - x\\x=-(\dfrac{1}{3} + x)\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x=\dfrac{1}{3} - x\\x=-\dfrac{1}{3} + x\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x + x=\dfrac{1}{3}\\x - x=-\dfrac{1}{3}\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}2x=\dfrac{1}{3}\\⇔x = \dfrac{1}6\\0x =-\dfrac{1}{3} (KTM)\end{array} \right.\)
Vậy `x = 1/6`
Hay nhất !
