Ta có:
$1+3+5+....+x = 1600$
$⇔ \dfrac{(x+1).[(x-1):2+1]}{2} = 1600$
$⇔ \dfrac{(x+1).(\dfrac{x}{2} - \dfrac{1}{2} + 1)}{2} = 1600$
$⇔ (x+1)(\dfrac{x+1}{2}) = 3200$
$⇔ \dfrac{(x+1)^2}{2} = 3200$
$⇔ (x+1)^2 = 6400$
$⇒$ \(\left[ \begin{array}{l}x=79\\x=-81(KTM)\end{array} \right.\)
Vậy $x=79$