`a,4(x+1)^2+(2x-1)^2-8(x-1)(x+1)=13`
`⇔4(x^2+2x+1)+4x^2-4x+1-8(x^2-1)=13`
`⇔4x^2+8x+4+4x^2-4x+1-8x^2+8=13`
`⇔4x=0`
`⇔x=0`
`b,x^2-4x-5=0`
`⇔x^2+x-5x-5=0`
`⇔x(x+1)-5(x+1)=0`
`⇔(x-5)(x+1)=0`
`⇔` \(\left[ \begin{array}{l}x-5=0\\x+1=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=5\\x=-1\end{array} \right.\)