1a. $\frac{1}{3}$ +( $\frac{1}{5}$ - $\frac{1}{7}$ )
= $\frac{1}{3}$ + $\frac{1}{5}$ - $\frac{1}{7}$
= $\frac{35}{105}$ + $\frac{21}{105}$ - $\frac{15}{105}$
= $\frac{35+21+15}{105}$
= $\frac{41}{105}$
b. $\frac{3}{5}$ - ( $\frac{3}{4}$ - $\frac{1}{2}$ )
= $\frac{3}{5}$ - $\frac{3}{4}$ + $\frac{1}{2}$
= $\frac{12}{20}$ - $\frac{15}{20}$ + $\frac{10}{20}$
= $\frac{12-15+10}{20}$
= $\frac{7}{20}$
3. $\frac{1}{ab+a+1}$ + $\frac{1}{bc+b+1}$ + $\frac{1}{abc+bc+b}$ ( cho abc=1 )
bạn xem lại đề có sai ko nhé
bài 2 mk ko bt làm sorry :(