Đáp án: + ) \(\left[ \begin{array}{l}x=9/14\\x=-51/14\end{array} \right.\)
+ ) x = $\frac{-7}{9}$
Giải thích các bước giải:
+ ) $\frac{|2x+3|}{5}$ = $\frac{6}{7}$
|2x+3| = $\frac{6}{7}$ . 5
|2x+3| = $\frac{30}{7}$
→ \(\left[ \begin{array}{l}2x+3=30/7\\2x+3=-30/7\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x=30/7-3\\2x=-30/7-3\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x=9/7\\2x=-51/7\end{array} \right.\)
→ \(\left[ \begin{array}{l}x=9/7:2\\x=-51/7:2\end{array} \right.\)
→ \(\left[ \begin{array}{l}x=9/14\\x=-51/14\end{array} \right.\)
+ ) 3x + $\frac{6}{2}$ = $\frac{6}{9}$
3x = $\frac{6}{9}$ - $\frac{6}{2}$
3x = $\frac{-7}{3}$
x = $\frac{-7}{3}$ : 3
x = $\frac{-7}{9}$
