Đáp án: $\dfrac{-7}{6}=\dfrac{-1}{12}+\dfrac{-1}{4}+\dfrac{-1}{3}+\dfrac{-1}{2}$
Giải thích các bước giải:
Ta có:
$\dfrac{-7}{6}=-\dfrac{7}{6}$
$\to \dfrac{-7}{6}=-\dfrac{14}{12}$
$\to \dfrac{-7}{6}=-\dfrac{1+3+4+6}{12}$
$\to \dfrac{-7}{6}=-(\dfrac{1}{12}+\dfrac{3}{12}+\dfrac{4}{12}+\dfrac{6}{12})$
$\to \dfrac{-7}{6}=-(\dfrac{1}{12}+\dfrac{1}{4}+\dfrac{1}{3}+\dfrac{1}{2})$
$\to \dfrac{-7}{6}=-\dfrac{1}{12}-\dfrac{1}{4}-\dfrac{1}{3}-\dfrac{1}{2}$
$\to \dfrac{-7}{6}=\dfrac{-1}{12}+\dfrac{-1}{4}+\dfrac{-1}{3}+\dfrac{-1}{2}$
