Đáp án:
$\dfrac{2585}{714}$
Giải thích các bước giải:
$\dfrac{18}{5}+\dfrac{18}{7}+(-1,4)+\dfrac{3}{34}+\left ( \dfrac{-1}{5} \right )+\left ( \dfrac{53}{51} \right )\\
=\dfrac{18}{5}+\dfrac{18}{7}-\dfrac{14}{10}+\dfrac{3}{34}-\dfrac{1}{5}-\dfrac{53}{51}\\
=\left (\dfrac{18}{5}-\dfrac{1}{5} \right )+\dfrac{18}{7}-\dfrac{7}{5}+\dfrac{3}{34}-\dfrac{53}{51}\\
=\dfrac{17}{5}-\dfrac{7}{5}+\dfrac{18}{7}+\dfrac{3}{34}-\dfrac{53}{51}\\ =\dfrac{10}{5}+\dfrac{18}{7}+\dfrac{3}{34}-\dfrac{53}{51}\\ =2+\dfrac{18}{7}+\dfrac{3}{34}-\dfrac{53}{51}\\
=\dfrac{2.3570}{3570}+\dfrac{18.510}{3570}+\dfrac{3.105}{3570}-\dfrac{53.70}{3570}\\
=\dfrac{12925}{3570}=\dfrac{2585}{714}$
