Đáp án:
\(\begin{array}{l}
a)\\
CTHH:CO\\
b)\\
CTHH:Mn{O_2}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
2)\\
a)\\
CTHH:{C_x}{O_y}\\
\% O = 100 - 42,86 = 57,14\% \\
x:y = \dfrac{{42,86}}{{12}}:\dfrac{{57,14}}{{16}} = 3,57:3,57 = 1:1\\
\Rightarrow CTHH:CO\\
b)\\
CTHH:M{n_x}{O_y}\\
\% O = 100 - 63,22 = 36,78\% \\
x:y = \dfrac{{63,22}}{{55}}:\dfrac{{36,78}}{{16}} = 1,15:2,3 = 1:2\\
\Rightarrow CTHH:Mn{O_2}
\end{array}\)
