Đáp án:
$\begin{array}{l}
y = {x^3} - 3m{x^2} + 7\\
\Rightarrow y' = 3{x^2} - 6mx\\
= 3x\left( {x - 2m} \right) = 0\\
\Rightarrow \left[ \begin{array}{l}
x = 0\\
x = 2m
\end{array} \right.\\
y' > 0\,khi:x \in \left( {10; + \infty } \right)\\
\Rightarrow 2m \le 10\\
\Rightarrow m \le 5
\end{array}$