Đáp án:
$1) \dfrac{11}{2}\\
2)
3$
Giải thích các bước giải:
$1) \dfrac{2}{7}.15\dfrac{1}{3}-29\dfrac{1}{3}:\dfrac{7}{2}+|-9,5|\\
=\dfrac{2}{7}.15\dfrac{1}{3}-29\dfrac{1}{3}.\dfrac{2}{7}+\dfrac{19}{2}\\
=\dfrac{2}{7}.\left ( 15-29+\dfrac{1}{3}-\dfrac{1}{3} \right )+\dfrac{19}{2}\\
=\dfrac{2}{7}.(-14)+\dfrac{19}{2}\\
=-4+\dfrac{19}{2}\\
=\dfrac{-8}{2}+\dfrac{19}{2}\\
=\dfrac{11}{2}\\
2)
3\dfrac{2}{3}+\dfrac{4}{9}-\left | -1\dfrac{2}{3} \right |-\dfrac{-5}{9}\\
=3\dfrac{2}{3}+\dfrac{4}{9}-1\dfrac{2}{3}+\dfrac{5}{9}\\
=\left ( 3-1+\dfrac{2}{3}-\dfrac{2}{3} \right )+\left ( \dfrac{4}{9}+\dfrac{5}{9} \right )\\
=2+1\\
=3$
