Đáp án:
Giải thích các bước giải:
ĐKXĐ:$\left \{ {{x≥2/3} \atop {x≥1}} \right.$
`\sqrt{3x-2}+\sqrt{x-1}=3`
`<=>(\sqrt{3x-2}+\sqrt{x-1})^2=3^2`
`<=>4x-3+2\sqrt{3x-2}.\sqrt{x-1}=9`
`<=>4x-12+2\sqrt{3x-2}.\sqrt{x-1}=0`
`<=>2x-6+\sqrt{3x-2}.\sqrt{x-1}=0`
`<=>2x-6=-\sqrt{3x-2}.\sqrt{x-1}`
`<=>(2x-6)^2=(-\sqrt{3x-2}.\sqrt{x-1})^2`
`<=>4x^2-24x+36=3x^2-3x-2x+2`
`<=>x^2-19x+34=0`
`<=>x^2-2x-17x+34=0`
`<=>(x-2)(x-17)=0`
`<=>`\(\left[ \begin{array}{l}x=2\\x=17\end{array} \right.\)
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