Đáp án:
\({m_{Zn{{(OH)}_2}}} = 61,875g\)
Giải thích các bước giải:
\(\begin{array}{l}
{n_{NaOH}} = 0,75mol\\
{n_{KOH}} = 0,5mol\\
{n_{ZnC{l_2}}} = 0,25mol\\
{n_{ZnS{O_4}}} = 0,375mol\\
\to {n_{O{H^ - }}} = {n_{NaOH}} + {n_{KOH}} = 1,25mol\\
\to {n_{Z{n^{2 + }}}} = {n_{ZnC{l_2}}} + {n_{ZnS{O_4}}} = 0,625mol\\
Z{n^{2 + }} + 2O{H^ - } \to Zn{(OH)_2}\\
{n_{Z{n^{2 + }}}} = \dfrac{1}{2}{n_{O{H^ - }}} = 0,625mol\\
\to {n_{Zn{{(OH)}_2}}} = {n_{Z{n^{2 + }}}} = 0,625mol\\
\to {m_{Zn{{(OH)}_2}}} = 61,875g
\end{array}\)