1. (2x -3) . (6 -2x) = 0
TH1 :
2x -3 = 0
2x = 3
x = 3:2
x = $\dfrac{3}{2}$
TH2 :
6 -2x = 0
2x = 6
x = 6 : 2
x= 3
2.$x:\dfrac{3}{4}+ \dfrac{1}{4}= \dfrac{-2}{3}$
$x:\dfrac{3}{4}= \dfrac{-2}{3}- \dfrac{1}{4}$
$x:\dfrac{3}{4}= \dfrac{-11}{12}$
$x= \dfrac{-11}{12}.\dfrac{3}{4}$
$x= \dfrac{-11}{16}$