Giải thích các bước giải:
11, `3^(2x+2)=9^10`
`=> 3^(2x + 2) = (3^2)^(10)`
`=> 3^(2x + 2) = 3^(20)`
`=> 2x + 2 = 20`
`=>2x = 18`
`=> x = 9`
Vậy `x=9`
12, `2^(3-2x) = 8^3`
`=> 2^(3 - 2x) = (2^3)^3`
`=> 2^(3 - 2x) = 2^9`
`=> 3 - 2x = 9`
`=> 2x = -6`
`=> x = -3`
Vậy `x=-3`
13, `2^(5x + 2) = 8^9`
`=> 2^(5x + 2) = (2^3)^9`
`=> 2^(5x + 2) = 2^(27)`
`=> 5x +2 = 27`
`=> 5x = 25`
`=> x=5`
Vậy `x=5`
14, `2^(6 + 5x) = 16^9`
`=> 2^(6 + 5x) = (2^4)^9`
`=> 2^(6+5x) = 2^(36)`
`=> 6 + 5x = 36`
`=> 5x = 30`
`=> x = 6`
Vậy `x=6`
15, `2^(3x + 1) = 32^2`
`=> 2^(3x + 1) = (2^5)^2`
`=> 2^(3x+1) = 2^(10)`
`=> 3x+1=10`
`=>3x=9`
`=>x=3`
Vậy `x=3`