Đáp án: \(\left[ \begin{array}{l}x = \dfrac{\pi}{2} + k2\pi\\x = -\dfrac{\pi}{6} + k2\pi\end{array} \right.\) `(k ∈ ZZ)`
Giải thích các bước giải:
`sin x + sqrt{3}cos x = 1`
`<=> 1/(2)sin x + (\sqrt{3})/(2)cos x = 1/2`
`<=> cos (x - π/6) = cos (π/3)`
`<=> x - π/6 = ±π/3 + k2π`
`<=>` \(\left[ \begin{array}{l}x = \dfrac{\pi}{2} + k2\pi\\x = -\dfrac{\pi}{6} + k2\pi\end{array} \right.\) `(k ∈ ZZ)`