Đáp án:
$⇒A=\dfrac{-5}{2}$
Giải thích các bước giải:
$C1:A=(6-\dfrac{2}{3}+\dfrac{1}{2})-(5+\dfrac{5}{3}-\dfrac{3}{2})-(3-\dfrac{7}{3}+\dfrac{5}{2})$
$⇒A=\dfrac{35}{6}-\dfrac{31}{6}-\dfrac{19}{6}$
$⇒A=\dfrac{35-31-19}{6}$
$⇒A=\dfrac{-15}{6}$
$⇒A=\dfrac{-5}{2}$
$C2:A=(6-\dfrac{2}{3}+\dfrac{1}{2})-(5+\dfrac{5}{3}-\dfrac{3}{2})-(3-\dfrac{7}{3}+\dfrac{5}{2})$
$⇒A=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}$
$⇒A=(6-5-3)+(\dfrac{-2}{3}+\dfrac{-5}{3}+\dfrac{7}{3})+(\dfrac{1}{2}+\dfrac{3}{2}+\dfrac{-5}{2})$
$⇒A=-2+0+\dfrac{-1}{2}$
$⇒A=\dfrac{-5}{2}$
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