$x-y=2m=-4$
$⇒2m=-4$
$⇒m=-2$
$2x-my=4$
$⇒2x+2y=4$
$⇒x+y=2$
$⇒x=(2-4):2=-1$
$⇒y=2-(-1)=3$
Vậy `(x; y)=(-1; 3)`
C2:
$\left \{ {{2x-my=4} \atop {x-y=2m}} \right.$
$⇒\left \{ {{2x+2y=4} \atop {x-y=-4}} \right.$
$⇒\left \{ {{x+y=2} \atop {x-y=-4}} \right.$
$⇒\left \{ {{x=-1} \atop {y=3}} \right.$
Vậy `(x; y)=(-1; 3)`