Đáp án:
\(\begin{array}{l} a,\ C_{M_{NaOH}}=1\ M.\\ b,\ V_{\text{dd H$_2$SO$_4$}}=107,456\ ml.\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\ PTHH:Na_2O+H_2O\to 2NaOH\\ n_{Na_2O}=\dfrac{15,5}{62}=0,25\ mol.\\ Theo\ pt:\ n_{NaOH}=2n_{Na_2O}=0,5\ mol.\\ ⇒C_{M_{NaOH}}=\dfrac{0,5}{0,5}=1\ M.\\ b,\ PTHH:H_2SO_4+2NaOH\to Na_2SO_4+2H_2O\\ Theo\ pt:\ n_{H_2SO_4}=\dfrac{1}{2}n_{NaOH}=0,25\ mol.\\ ⇒m_{\text{dd H$_2$SO$_4$}}=\dfrac{0,25\times 98}{20\%}=122,5\ g.\\ ⇒V_{\text{dd H$_2$SO$_4$}}=\dfrac{122,5}{1,14}=107,456\ ml.\end{array}\)
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