Đáp án:
\(\begin{array}{l}
a)\\
{\% ^{41}}K = 6,738\% \\
\% {m_{^{41}K}} = 3,9\% \\
b)\\
{N_{^{41}K}} = 1,9 \times {10^{21}}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{\% ^{41}}K = 100 - 93,25 - 0,012 = 6,738\% \\
\overline {{M_K}} = \dfrac{{39 \times 93,25 + 40 \times 0,012 + 41 \times 6,738}}{{100}} = 39,13488\\
{M_{{K_3}P{O_4}}} = 39,13488 \times 3 + 30,97 + 16 \times 4 = 212,37464\\
\% {m_{^{41}K}} = \dfrac{{3 \times 6,738\% \times 41}}{{212,37464}} \times 100\% = 3,9\% \\
b)\\
{n_{{K_3}P{O_4}}} = \dfrac{{10}}{{212,37464}} = 0,047\,mol\\
{N_{^{41}K}} = 0,047 \times 6,738\% \times 6 \times {10^{23}} = 1,9 \times {10^{21}}
\end{array}\)