Đáp án:
$\text{x = 0 hoặc x = -2.}$
Giải thích các bước giải:
$\text{$0,25x^3$ + $x^2$ + x = 0.}$
$\text{⇒ x.($0,25x^2$ + x + 1) = 0.}$
$\text{⇒ x.[(0,5$x)^2$ + 2.0,5x.1 + $1^2$) = 0.}$
$\text{⇒ x.$(0,5x+1)^2$ = 0.}$
$\text{⇒}$ \(\left[ \begin{array}{l}x=0.\\(0,5x+1)^2=0.\end{array} \right.\)
$\text{⇒}$ \(\left[ \begin{array}{l}x=0.\\0,5x+1=0.\end{array} \right.\)
$\text{⇒}$ \(\left[ \begin{array}{l}x=0.\\0,5x=-1.\end{array} \right.\)
$\text{⇒}$ \(\left[ \begin{array}{l}x=0.\\x=(-1)÷0,5.\end{array} \right.\)
$\text{⇒}$ \(\left[ \begin{array}{l}x=0.\\x=-2.\end{array} \right.\)
$\text{Vậy x = 0 hoặc x = -2.}$
