Đáp án:
\(\omega 1 = 12{\omega _2}\)
\({v_1} = 16{v_2}\)
\({a_1} = 192{a_2}\)
Giải thích các bước giải:
Ta có:
\(\dfrac{{{\omega _1}}}{{{\omega _2}}} = \dfrac{{\frac{{2\pi }}{{{T_1}}}}}{{\dfrac{{2\pi }}{{{T_2}}}}} = \dfrac{{{T_2}}}{{{T_1}}} = \dfrac{{43200}}{{3600}} = 12\)
Ta có:
\(\begin{array}{*{20}{l}}
{\dfrac{{{v_1}}}{{{v_2}}} = \dfrac{{{\omega _1}{r_1}}}{{{\omega _2}{r_2}}} = \dfrac{{12{r_1}}}{{\frac{3}{4}{r_2}}} = 16}\\
{{\rm{\;}} \Rightarrow {v_1} = 16{v_2}}
\end{array}\)
\(\begin{array}{*{20}{l}}
{\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{{{\omega _1}^2{r_1}}}{{\omega _2^2{r_2}}} = \dfrac{{{{12}^2}.{r_1}}}{{\dfrac{3}{4}{r_2}}} = 192}\\
{ \Rightarrow {a_1} = 192{a_2}}
\end{array}\)
