Giải thích các bước giải:
\(\begin{array}{l}
Zn + CuS{O_4} \to ZnS{O_4} + Cu\\
{m_{{\rm{CuS}}{O_4}}} = \dfrac{{20 \times 10\% }}{{100\% }} = 2g\\
\to {n_{{\rm{CuS}}{O_4}}} = 0,0125mol\\
\to {n_{Zn}} = {n_{{\rm{CuS}}{O_4}}} = 0,0125mol \to {m_{Zn}} = 0,8125g\\
\to {n_{ZnS{O_4}}} = {n_{{\rm{CuS}}{O_4}}} = 0,0125mol \to {m_{ZnS{O_4}}} = 2,0125g\\
{n_{Cu}} = {n_{{\rm{CuS}}{O_4}}} = 0,0125mol \to {m_{Cu}} = 0,8g\\
{m_{{\rm{dd}}saupu}} = {m_{Zn}} + {m_{{\rm{ddCuS}}{O_4}}} - {m_{Cu}} = 20,0125g\\
\to C{\% _{ZnS{O_4}}} = \dfrac{{2,0125}}{{20,0125}} \times 100\% = 10,06\%
\end{array}\)
