Đáp án:
Giải thích các bước giải:
`a) (x+2)^2-(x-2)(x+2)=0`
`⇔ (x+2)(x+2-x+2)=0`
`⇔4(x+2)=0`
`⇔x+2=0`
`⇔x=-2`
`b)(2x-1)^2-(x-3)^2=0`
`⇔(2x-1+x-3)(2x-1-x+3)=0`
`⇔(3x-4)(x+2)=0`
`⇔`\(\left[ \begin{array}{l}3x-4=0\\x+2=0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x=\frac{4}{3}\\x=-2\end{array} \right.\)