$\sqrt[]{4x-4}+$ $\sqrt[]{25x-25}-$ $\frac{1}{4}$ $\sqrt[]{16x-16}=24$ (ĐKXĐ:$x\neq1$)
⇔$\sqrt[]{4(x-1)}+$ $\sqrt[]{25(x-1)}-$ $\frac{1}{4}$ $\sqrt[]{16(x-1)}=24$
⇔$2\sqrt[]{(x-1)}+$ $5\sqrt[]{(x-1)}-$ $\frac{4}{4}$ $\sqrt[]{(x-1)}=24$
⇔$\sqrt[]{x-1}$( $2+5-1)^{}=24$
⇔$\sqrt[]{x-1}$ =$24÷6^{}=4$
⇔$x-1^{}=4^{2}=16$
⇔$x^{}=16+1=17$ (T'M ĐKXĐ)
-Mời bạn tham khảo!
