Em tham khảo nha:
\(\begin{array}{l}
a)\\
HCl + KOH \to KCl + {H_2}O\\
C{H_3}COOH + KOH \to C{H_3}COOK + {H_2}O\\
hh:HCl(a\,mol),C{H_3}COOH(b\,mol)\\
{n_{KOH}} = 0,003 \times 1 = 0,003\,mol\\
a + b = 0,003\\
74,5a + 98b = 0,235\\
\Rightarrow a \approx 0,0025;b \approx 0,0005\\
{C_M}HCl = \dfrac{{0,0025}}{{0,01}} = 0,25M\\
{C_M}C{H_3}COOH = \dfrac{{0,0005}}{{0,01}} = 0,05M\\
b)\\
V \times 0,02 \times 2 + 0,01 \times V = 0,003\\
\Rightarrow V = 0,06l = 60ml
\end{array}\)