Đáp án:
B1:
\(\dfrac{8}{3}\)
Giải thích các bước giải:
\(\begin{array}{l}
B1:\\
\dfrac{{{{\left( {{3^2}} \right)}^2}.{{\left( {{2^2}} \right)}^5}}}{{{2^5}{{.3}^5}{{.3}^2}}} = \dfrac{{{3^4}{{.2}^{10}}}}{{{2^7}{{.3}^5}}}\\
= \dfrac{{{2^3}}}{3} = \dfrac{8}{3}\\
B2:\\
DK:x \ne \dfrac{1}{2}\\
\dfrac{{2x - 1}}{{ - 2}} = \dfrac{{18}}{{1 - 2x}}\\
\to \dfrac{{1 - 2x}}{2} = \dfrac{{18}}{{1 - 2x}}\\
\to {\left( {1 - 2x} \right)^2} = 36\\
\to \left| {1 - 2x} \right| = 6\\
\to \left[ \begin{array}{l}
1 - 2x = 6\\
1 - 2x = - 6
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = - \dfrac{5}{2}\\
x = \dfrac{7}{2}
\end{array} \right.
\end{array}\)
