$sinx-cosx=-\sqrt{2}$ (1)
Chia hai vế pt (1) cho $\sqrt{2}$:
(1) $\Leftrightarrow \dfrac{1}{\sqrt{2}}sinx-\dfrac{1}{\sqrt{2}}cosx=-1$
$\Leftrightarrow sin(x-\dfrac{\pi}{4})=-1$
$\Leftrightarrow x - \dfrac{\pi}{4}=-\dfrac{\pi}{2}+k2\pi$ (k€Z)
$\Leftrightarrow x=-\dfrac{\pi}{4}+k2\pi$ (k€Z)