Giải thích các bước giải:
x-$\frac{2}{12}$=$\frac{3}{x-2}$
⇔ $\frac{12x}{12}$-$\frac{2}{12}$=$\frac{3}{x-2}$
⇔ $\frac{12x-2}{12}$=$\frac{3}{x-2}$
⇔ (12x-2)(x-2)=3.12
⇔ 12x²-24x-2x+4-3.12=0
⇔ 12x²-26x-32=0
⇔ 4(3x²-6x-9)=0
⇔ 12(x²-2x-3)=0
⇔ x²-x+3x-3=0
⇔ x(x-1)+3(x-1)=0
⇔ (x-1)(x+3)=0
⇔ \(\left[ \begin{array}{l}x-1=0\\x+3=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=1\\x=-3\end{array} \right.\)
Vậy S={1;-3}
