$a,2x(2x-1)²-4x(x+2)(x-2)-4x(x+1)²$
$=2x[(2x)²-2.2x.1+1²]-4x(x²-2²)-4x(x²+2x.1+1²)$
$=2x(4x²-4x+1)-4x(x²-4)-4x(x²+2x+1)$
$=8x³-8x²+2x-4x³+16x-4x³-8x²-4x$
$=14x-16x²$
$b,(2+1)(2²+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=3(2²+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=[(2²)²-1²](2^4+1)(2^8+1)(2^{16}+1)$
$=(2^4-1)(2^4+1)(2^8+1)(2^{16}+1)$
$=[(2^4)²-1²](2^8+1)(2^{16}+1)$
$=(2^8-1)(2^8+1)(2^{16}+1)$
$=[(2^8)^2-1²](2^{16}+1)$
$=(2^{16}-1)(2^{16}+1)$
$=(2^{16})²-1²$
$=2^{32}-1$