Đáp án:
16,95g
Giải thích các bước giải:
$\%N= 11,966\% ⇒M_X=14:11,966\%=117⇒ R+R'=57$
$X+KOH$
$NH_2-R-COOR'+KOH\to NH_2RCOOK+R'OH$
$R'OH+Na\to R'ONa+\dfrac{1}{2}H_2$
$n_{H_2}=\dfrac{1}{2}.n_{R'OH} ⇒ n_{R'OH}=0,15\ mol=n_{R'ONa}$
$n_{Na\ pư}=2.n_{H_2}=0,15\ mol\\⇒m_{chất\ rắn}=23-0,15.23+m_{R'ONa}\\⇒m_{R'ONa}=12,3⇒R'=43=C_3H_7$
$⇒R=14 = -CH_2-$
$m=m_{H_2NCH_2COOK}=0,15.113=16,95g$