Em tham khảo nha:
\(\begin{array}{l}
1)\\
a)\\
4Na + {O_2} \xrightarrow{t^0} 2N{a_2}O\\
N{a_2}O + C{O_2} \to N{a_2}C{O_3}\\
N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O\\
2NaCl + 2{H_2}O \to 2NaOH + C{l_2} + {H_2}\\
b)\\
4Na + {O_2} \xrightarrow{t^0} 2N{a_2}O\\
N{a_2}O + S{O_2} \to N{a_2}S{O_3}\\
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
NaCl + AgN{O_3} \to NaN{O_3} + AgCl\\
2)\\
a)\\
CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
Cu{(OH)_2} \xrightarrow{t^0} CuO + {H_2}O\\
b)\\
{n_{Cu{{(OH)}_2}}} = \dfrac{{9,8}}{{98}} = 0,1\,mol\\
{n_{CuO}} = {n_{Cu{{(OH)}_2}}} = 0,1\,mol\\
{m_{CuO}} = 0,1 \times 80 = 8g\\
c)\\
{n_{CuC{l_2}}} = {n_{Cu{{(OH)}_2}}} = 0,1\,mol\\
x = {m_{{\rm{dd}}CuC{l_2}}} = \dfrac{{0,1 \times 135}}{{25\% }} = 54g
\end{array}\)