Đáp án:
Bạn tham khảo lời giải nhé!!
Giải thích các bước giải:
\(\begin{array}{*{20}{l}}
{3P + 5HN{O_3} + 2{H_2}O \to 3{H_3}P{O_4} + 5NO}\\
{3P + 5{H^ + } + 5N{O_3}^ - {\rm{ \;}} + 2{H_2}O \to 3{H_3}P{O_4} + 5NO}
\end{array}\)
\(\begin{array}{l}
Fe + 4HN{O_3} \to Fe{(N{O_3})_3} + NO + 2{H_2}O\\
Fe + 4{H^ + } + N{O_3}^ - \to F{e^{3 + }} + NO + 2{H_2}O
\end{array}\)
\(\begin{array}{l}
3Cu + 8HN{O_3} \to 3Cu{(N{O_3})_2} + 2NO + 4{H_2}O\\
3Cu + 8{H^ + } + 2N{O_3}^ - \to 3C{u^{2 + }} + 2NO + 4{H_2}O
\end{array}\)
\(\begin{array}{l}
3FeO + 10HN{O_3} \to 3Fe{(N{O_3})_3} + NO + 5{H_2}O\\
3FeO + 10{H^ + } + N{O_3}^ - \to 3F{e^{3 + }} + NO + 5{H_2}O
\end{array}\)
\(\begin{array}{l}
F{e_2}{O_3} + 6HN{O_3} \to 2Fe{(N{O_3})_3} + 3{H_2}O\\
F{e_2}{O_3} + 6{H^ + } \to 2F{e^{3 + }} + 3{H_2}O
\end{array}\)
\(\begin{array}{l}
3F{e_3}{O_4} + 28HN{O_3} \to 9Fe{(N{O_3})_3} + NO + 14{H_2}O\\
3F{e_3}{O_4} + 28{H^ + } + N{O_3}^ - \to 9F{e^{3 + }} + NO + 14{H_2}O
\end{array}\)
\(\begin{array}{l}
8Al + 30HN{O_3} \to 8Al{(N{O_3})_3} + 3{N_2}O + 15{H_2}O\\
8Al + 30{H^ + } + 6N{O_3}^ - \to 8A{l^{3 + }} + 3{N_2}O + 15{H_2}O
\end{array}\)
\(\begin{array}{l}
5Mg + 12HN{O_3} \to 5Mg{(N{O_3})_2} + {N_2} + 6{H_2}O\\
5Mg + 12{H^ + } + 2N{O_3}^ - \to 5M{g^{2 + }} + {N_2} + 6{H_2}O
\end{array}\)
\(\begin{array}{l}
4Zn + 10HN{O_3} \to 4Zn{(N{O_3})_2} + N{H_4}N{O_3} + 3{H_2}O\\
4Zn + 10{H^ + } + N{O_3}^ - \to 4Z{n^{2 + }} + N{H_4}^ + + 3{H_2}O
\end{array}\)
\(\begin{array}{l}
(5x - 2y)Fe + 6(3x - y)HN{O_3} \to (5x - 2y)Fe{(N{O_3})_3} + 3{N_x}{O_y} + 3(3x - y){H_2}O\\
(5x - 2y)Fe + 6(3x - y){H^ + } + 3xN{O_3}^ - \to (5x - 2y)F{e^{3 + }} + 3{N_x}{O_y} + 3(3x - y){H_2}O
\end{array}\)
\(\begin{array}{l}
3F{e_x}{O_y} + (12x - 2y)HN{O_3} \to 3xFe{(N{O_3})_3} + (3x - 2y)NO + (6x - y){H_2}O\\
3F{e_x}{O_y} + (12x - 2y){H^ + } + (3x - 2y)N{O_3}^ - \to 3xF{e^{3 + }} + (3x - 2y)NO + (6x - y){H_2}O
\end{array}\)
\(\begin{array}{l}
13Al + 60HN{O_3} \to 13Al{(N{O_3})_3} + 9NO + 12N{O_2} + 30{H_2}O\\
13Al + 60{H^ + } + 21N{O_3}^ - \to 13A{l^{3 + }} + 9NO + 12N{O_2} + 30{H_2}O
\end{array}\)
