Đáp án:
\(\begin{array}{l}
b)\\
{m_{Zn}} = 6,5g\\
c)\\
{m_{ZnC{l_2}}} = 13,6g
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
b)\\
{n_{{H_2}}} = \dfrac{V}{{22,4}} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,1\,mol\\
{m_{Zn}} = n \times M = 0,1 \times 65 = 6,5g\\
b)\\
{n_{ZnC{l_2}}} = {n_{Zn}} = 0,1\,mol\\
{m_{ZnC{l_2}}} = n \times M = 0,1 \times 136 = 13,6g
\end{array}\)