$A=(\frac{1}{\sqrt{x}-1}-$ $\frac{1}{\sqrt{x}+1})($ $\sqrt{x}-1)$
$=\frac{\sqrt{x}+1-\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}($ $\sqrt{x}-1)$
$=\frac{2}{(\sqrt{x}-1)(\sqrt{x}+1)}($ $\sqrt{x}-1)$
$=$$\frac{2}{\sqrt{x}+1}$
$b,A=\frac{1}{2}⇔\frac{2}{\sqrt{x}+1}=\frac{1}{2}$
$⇔\sqrt{x}+1=4$
$⇔\sqrt{x}=3$
$⇔x=9$
đây