Đáp án:
\(\begin{array}{l}
a)\\
{n_{hh}} = 2\,mol\\
b)\\
{V_{hh}} = 44,8l\\
c)\\
{m_{hh}} = 54,8g\\
d)\\
{M_{hh}} = 27,4(g/mol)
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{n_{{O_2}}} = \dfrac{m}{M} = \dfrac{{6,4}}{{32}} = 0,2\,mol\\
{n_{C{O_2}}} = \dfrac{m}{M} = \dfrac{{4,4}}{{44}} = 0,1\,mol\\
{n_{NO}} = \dfrac{m}{M} = \dfrac{{36}}{{30}} = 1,2\,mol\\
{n_{C{H_4}}} = \dfrac{m}{M} = \dfrac{8}{{16}} = 0,5\,mol\\
{n_{hh}} = 0,2 + 0,1 + 1,2 + 0,5 = 2\,mol\\
b)\\
{V_{hh}} = 2 \times 22,4 = 44,8l\\
c)\\
{m_{hh}} = 6,4 + 4,4 + 36 + 8 = 54,8g\\
d)\\
{M_{hh}} = \dfrac{{{m_{hh}}}}{{{n_{hh}}}} = \dfrac{{54,8}}{2} = 27,4(g/mol)
\end{array}\)
