`300ml=0,3l`
`200ml=0,2l`
`n_{CuCl_{2}}=C_{M}.V_{dd}=0,5.0,3=0,15(mol)`
`PTHH:CuCl_{2}+2NaOH->Cu(OH)_{2}↓+2NaCl`
`(mol)` `0,15` `0,3` `0,15` `0,3`
`PTHH:Cu(OH)_{2}->CuO+H_{2}O`
`(mol)` `0,15` `0,15` `0,15`
`m_{CuO}=n.M=0,15.80=12(g)`
c) `V_{ddaCl}=0.3+0,2=0,5(l)`
`C_{M_{NaCl}}=n/V_{dd}=(0,3)/(0,5)=0,6(M)`