`n_(H_2) = 10.08 / 22.4 = 0.45 ( mol ) `
Gọi `n_(Mg) = x ` ; ` n_(Zn) = y`
` PT : Mg + 2HCl -> MgCl_2 + H_2`
` x - x`
` Zn + 2HCl -> ZnCl_2 + H_2`
` y - y`
ta có hệ PT : $\left \{ {{24x + 65y = 19} \atop {x + y = 0.45}} \right.$
=> $\left \{ {{x=0.25} \atop {y=0.2}} \right.$
`=> m_(Mg) = 0.25 * 24 = 6 ( g ) `
`m_(Zn) = 0.2 * 65 = 13 ( g ) `