Đáp án:
\(\begin{array}{l}
a)C{M_{NaCl}} = 1,33M\\
b){V_{S{O_2}}} = 5,6l\\
c){m_{NaCl}} = 29,25g
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
{n_{HCl}} = 0,5mol\\
\to {n_{N{a_2}S{O_3}}} = \dfrac{1}{2}{n_{HCl}} = 0,25mol\\
\to {V_{N{a_2}S{O_3}}} = \dfrac{{0,25}}{2} = 0,125l\\
a)\\
{n_{NaCl}} = {n_{HCl}} = 0,5mol\\
\to C{M_{NaCl}} = \dfrac{{0,5}}{{0,125 + 0,25}} = 1,33M\\
b)\\
{n_{S{O_2}}} = \dfrac{1}{2}{n_{HCl}} = 0,25mol\\
\to {V_{S{O_2}}} = 5,6l\\
c)\\
{m_{NaCl}} = 29,25g
\end{array}\)