Đáp án:
mXmY=73mXmY=73
mX+mY=160đvCmX+mY=160đvC
mX=160÷(7+3)×7=112đvCmX=160÷(7+3)×7=112đvC
mY=160−112=48đvCmY=160−112=48đvC
mX=2×NTK(X)mX=2×NTK(X)
2×NTK(X)=1122×NTK(X)=112
NTK(X)=1122NTK(X)=1122
NTK(X)=56đvC⇒FeNTK(X)=56đvC⇒Fe
mY=3×NTK(Y)mY=3×NTK(Y)
3×NTK(Y)=483×NTK(Y)=48
NTK(Y)=483NTK(Y)=483
NTK(Y)=16đvC⇒ONTK(Y)=16đvC⇒O
CTHH: Fe2O3
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