Đáp án:
Giải thích các bước giải:
Ta có:
$x^2+xy-2017x-2018y-6051=0\\\Leftrightarrow y=-\frac{x^2-2017x-6051}{x-2018}$
Suy ta ta có:
$x^2-2017x-6051\vdots x-2018\\\Leftrightarrow (x-2018)^2+2019x-4078375\vdots x-2018\\\Leftrightarrow 2019x-4078375\vdots x-2018\\\Leftrightarrow 2019(x-2018)-4033\vdots x-2018\\\Leftrightarrow 4033\vdots x-2018\\\Leftrightarrow x\in \{-2015; 1909; 1981; 2017; 2019\}\\\Rightarrow (x; y)=\{(-2015; 2013); (1909; -1947); (1981; -2091); (2017; -6051); (2019; 2013)\}$
