Đáp án:
$\dfrac{2\sqrt[]{c}(c\sqrt[]{c}+ab)}{a^\frac{3}{2}.b^\frac{3}{2}.c^\frac{3}{2}}$
Giải thích các bước giải:
$\dfrac{2}{\sqrt[]{a^{3}.b^{3}}}+$$\dfrac{2}{ \sqrt[]{a.b.c^{3}}}$
$=\dfrac{2}{ab\sqrt[]{ab}}+$$\dfrac{2}{ \sqrt[]{a.b.c^{3}}}$
$=\dfrac{2}{ab\sqrt[]{ab}}+$$\dfrac{2}{ c\sqrt[]{abc}}$
$=\dfrac{2c\sqrt{a}\sqrt{b}\sqrt{c}+2a^{\frac{3}{2}}b^{\frac{3}{2}}}{a^2b^2c\sqrt{c}}$
$=\dfrac{2\sqrt{a}\sqrt{b}\left(c\sqrt{c}+ab\right)}{a^2b^2c\sqrt{c}}$
$=\dfrac{2\left(c\sqrt{c}+ab\right)}{ca^{\frac{3}{2}}b^{\frac{3}{2}}\sqrt{c}}$
$=\dfrac{2\sqrt{c}\left(c\sqrt{c}+ab\right)}{c^2a^{\frac{3}{2}}b^{\frac{3}{2}}}$
