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luongthimailan04052007
2 năm trước
Hạt bụi có m= 1g mang điện tích q = -10^-6 C nằm cân bằng trong điện trường của tụ phẳng có các bản tụ nằm ngang d = 2cm ,lấy g= 10 m/s^2 .Khi điện tích của tụ giảm đi 20% để hạt bụi vẫn cân bằng thì phải thay đổi hiệu điện thế giữa 2 bản tụ điện như thế nào?
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