Đáp án:
\(\begin{array}{l}
5.\\
a.R = \dfrac{{24}}{7}\Omega \\
b.\\
{I_1} = \dfrac{7}{3}A\\
{I_2} = \dfrac{7}{4}A\\
6.\\
a.{Q_{thu}} = 1200000J\\
b.{Q_{toa}} = 672000J
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
5.\\
a.\\
R = \dfrac{{{R_1}{R_2}}}{{{R_1} + {R_2}}} = \dfrac{{6.8}}{{6 + 8}} = \dfrac{{24}}{7}\Omega \\
b.\\
{U_1} = {U_2} = U = 14V\\
{I_1} = \dfrac{{{U_1}}}{{{R_1}}} = \dfrac{{14}}{6} = \frac{7}{3}A\\
{I_2} = \dfrac{{{U_2}}}{{{R_2}}} = \dfrac{{14}}{8} = \frac{7}{4}A\\
6.\\
a.\\
{Q_{thu}} = Pt = 1000.1200 = 1200000J\\
b.\\
{Q_{toa}} = mc\Delta t = 2.4200(100 - 20) = 672000J
\end{array}\)