Đáp án:
\(\begin{array}{l}
a.\\
{R_{d1}} = 6\Omega \\
{R_{d2}} = 6\Omega \\
b.\\
{I_1} = 1A\\
{I_2} = 1A\\
c.\\
I = 2A
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.\\
{R_{d1}} = \dfrac{{U_{dm1}^2}}{{{P_{dm1}}}} = \dfrac{{{6^2}}}{6} = 6\Omega \\
{R_{d2}} = \dfrac{{U_{dm2}^2}}{{{P_{dm2}}}} = \dfrac{{{6^2}}}{6} = 6\Omega \\
b.\\
U = {U_{dm1}} = {U_{dm2}} = 6V
\end{array}\)
Suy ra cần mắc 2 đèn song song nhau.
\(\begin{array}{l}
{I_1} = {I_{dm1}} = \dfrac{{{P_{dm1}}}}{{{U_{dm1}}}} = \dfrac{6}{6} = 1A\\
{I_2} = {I_{dm2}} = \dfrac{{{P_{dm2}}}}{{{U_{dm2}}}} = \dfrac{6}{6} = 1A\\
c.\\
I = {I_1} + {I_2} = 1 + 1 = 2A
\end{array}\)