Đáp án:
Giải thích các bước giải:
$(x+\dfrac{1}{2})+(x+$ $\dfrac{1}{4})+(x+$ $\dfrac{1}{8})=1$
→$(x+x+x)+(\dfrac{1}{2}+$ $\dfrac{1}{4}+$ $\dfrac{1}{8})=1$
→ $3x+_{}$ $\dfrac{7}{8}=1$
→ $3x=1-\dfrac{7}{8}=$ $\dfrac{1}{8}$
→ $x=\dfrac{1}{8}:3=$ $\dfrac{1}{8}.$ $\dfrac{1}{3}=$ $\dfrac{1}{24}$