a)
Ta có:
\({M_{hh}} = {M_{C{H_4}}} = 12 + 1.4 = 16\)
Áp dụng quy tắc đường chéo:
\(\begin{array}{*{20}{c}}
{CO(28)}&{}&{14} \\
{}&{hh(16)}&{} \\
{{H_2}(2)}&{}&{12}
\end{array} \to \frac{{{V_{CO}}}}{{{V_{{H_2}}}}} = \frac{{14}}{{12}} = \frac{7}{6}\)
b)
Đốt cháy hỗn hợp
\(2CO + {O_2}\xrightarrow{{{t^o}}}2C{O_2}\)
\(2{H_2} + {O_2}\xrightarrow{{{t^o}}}2{H_2}O\)
\( \to {V_{{O_2}}} = \frac{1}{2}{V_{CO}} + \frac{1}{2}{V_{{H_2}}} = \frac{1}{2}{V_{hh}} = \frac{1}{2}.5,6 = 2,8{\text{ lít}}\)